python 二维数组90度旋转的方法

如下所示：

#!/usr/bin/env python
#-*- coding: utf-8 -*-
 
"""
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
[0, 1, 2, 3]
2维数组顺时针90度旋转后结果如下
[0, 0, 0, 0]
[1, 1, 1, 1]
[2, 2, 2, 2]
[3, 3, 3, 3]
[0][1] <==> [1][0]
[0][2] <==> [2][0]
[0][3] <==> [3][0]
[1][2] <==> [2][1]
[1][3] <==> [3][1]
[2][3] <==> [3][2]
"""
 
data=[[i for i in range(4)] for raw in range(4)]
for ele in data:
 print ele
a=len(data)
for i in range(a):#外层循环
 for j in range(i+1,len(data[i])): #内层循环
  #交换数据
  temp=data[i][j]
  data[i][j]=data[j][i]
  data[j][i]=temp
for ele in data:
 print ele