azhou 2019-11-10


SELECT DISTINCT
< select_list >
FROM
< left_table > < join_type >
JOIN < right_table > ON < join_condition >
WHERE
< where_condition >
GROUP BY
< group_by_list >
HAVING
< having_condition >
ORDER BY
< order_by_condition >
LIMIT < limit_number >
然而它的执行顺序是这样的
FROM <left_table>
ON <join_condition>
<join_type> JOIN <right_table>
WHERE <where_condition>
GROUP BY <group_by_list>
HAVING <having_condition>
SELECT
DISTINCT <select_list>
ORDER BY <order_by_condition>
LIMIT <limit_number>
虽然自己没想到是这样的,不过一看还是很自然和谐的,从哪里获取,不断的过滤条件,要选择一样或不一样的,排好序,那才知道要取前几条呢。
既然如此了,那就让我们一步步来看看其中的细节吧。
准备工作
1.创建测试数据库
create database testQueryCREATE TABLE table1
(
uid VARCHAR(10) NOT NULL,
name VARCHAR(10) NOT NULL,
PRIMARY KEY(uid)
)ENGINE=INNODB DEFAULT CHARSET=UTF8;
CREATE TABLE table2
(
oid INT NOT NULL auto_increment,
uid VARCHAR(10),
PRIMARY KEY(oid)
)ENGINE=INNODB DEFAULT CHARSET=UTF8;3.插入数据
INSERT INTO table1(uid,name) VALUES(‘aaa‘,‘mike‘),(‘bbb‘,‘jack‘),(‘ccc‘,‘mike‘),(‘ddd‘,‘mike‘); INSERT INTO table2(uid) VALUES(‘aaa‘),(‘aaa‘),(‘bbb‘),(‘bbb‘),(‘bbb‘),(‘ccc‘),(NULL);
4.最后想要的结果
SELECT
a.uid,
count(b.oid) AS total
FROM
table1 AS a
LEFT JOIN table2 AS b ON a.uid = b.uid
WHERE
a. NAME = ‘mike‘
GROUP BY
a.uid
HAVING
count(b.oid) < 2
ORDER BY
total DESC
LIMIT 1;mysql> select * from table1,table2; +-----+------+-----+------+ | uid | name | oid | uid | +-----+------+-----+------+ | aaa | mike | 1 | aaa | | bbb | jack | 1 | aaa | | ccc | mike | 1 | aaa | | ddd | mike | 1 | aaa | | aaa | mike | 2 | aaa | | bbb | jack | 2 | aaa | | ccc | mike | 2 | aaa | | ddd | mike | 2 | aaa | | aaa | mike | 3 | bbb | | bbb | jack | 3 | bbb | | ccc | mike | 3 | bbb | | ddd | mike | 3 | bbb | | aaa | mike | 4 | bbb | | bbb | jack | 4 | bbb | | ccc | mike | 4 | bbb | | ddd | mike | 4 | bbb | | aaa | mike | 5 | bbb | | bbb | jack | 5 | bbb | | ccc | mike | 5 | bbb | | ddd | mike | 5 | bbb | | aaa | mike | 6 | ccc | | bbb | jack | 6 | ccc | | ccc | mike | 6 | ccc | | ddd | mike | 6 | ccc | | aaa | mike | 7 | NULL | | bbb | jack | 7 | NULL | | ccc | mike | 7 | NULL | | ddd | mike | 7 | NULL | +-----+------+-----+------+ rows in set (0.00 sec)
mysql> SELECT
-> *
-> FROM
-> table1,
-> table2
-> WHERE
-> table1.uid = table2.uid
-> ;
+-----+------+-----+------+
| uid | name | oid | uid |
+-----+------+-----+------+
| aaa | mike | 1 | aaa |
| aaa | mike | 2 | aaa |
| bbb | jack | 3 | bbb |
| bbb | jack | 4 | bbb |
| bbb | jack | 5 | bbb |
| ccc | mike | 6 | ccc |
+-----+------+-----+------+
rows in set (0.00 sec)mysql> SELECT
-> *
-> FROM
-> table1 AS a
-> LEFT OUTER JOIN table2 AS b ON a.uid = b.uid;
+-----+------+------+------+
| uid | name | oid | uid |
+-----+------+------+------+
| aaa | mike | 1 | aaa |
| aaa | mike | 2 | aaa |
| bbb | jack | 3 | bbb |
| bbb | jack | 4 | bbb |
| bbb | jack | 5 | bbb |
| ccc | mike | 6 | ccc |
| ddd | mike | NULL | NULL |
+-----+------+------+------+
rows in set (0.00 sec)下面从网上找到一张很形象的关于‘SQL JOINS‘的解释图,如若侵犯了你的权益,请劳烦告知删除,谢谢。

mysql> SELECT
-> *
-> FROM
-> table1 AS a
-> LEFT OUTER JOIN table2 AS b ON a.uid = b.uid
-> WHERE
-> a. NAME = ‘mike‘;
+-----+------+------+------+
| uid | name | oid | uid |
+-----+------+------+------+
| aaa | mike | 1 | aaa |
| aaa | mike | 2 | aaa |
| ccc | mike | 6 | ccc |
| ddd | mike | NULL | NULL |
+-----+------+------+------+
rows in set (0.00 sec)mysql> SELECT
-> *
-> FROM
-> table1 AS a
-> LEFT OUTER JOIN table2 AS b ON a.uid = b.uid
-> WHERE
-> a. NAME = ‘mike‘
-> GROUP BY
-> a.uid;
+-----+------+------+------+
| uid | name | oid | uid |
+-----+------+------+------+
| aaa | mike | 1 | aaa |
| ccc | mike | 6 | ccc |
| ddd | mike | NULL | NULL |
+-----+------+------+------+
rows in set (0.00 sec)mysql> SELECT
-> *
-> FROM
-> table1 AS a
-> LEFT OUTER JOIN table2 AS b ON a.uid = b.uid
-> WHERE
-> a. NAME = ‘mike‘
-> GROUP BY
-> a.uid
-> HAVING
-> count(b.oid) < 2;
+-----+------+------+------+
| uid | name | oid | uid |
+-----+------+------+------+
| ccc | mike | 6 | ccc |
| ddd | mike | NULL | NULL |
+-----+------+------+------+
rows in set (0.00 sec)mysql> SELECT
-> a.uid,
-> count(b.oid) AS total
-> FROM
-> table1 AS a
-> LEFT OUTER JOIN table2 AS b ON a.uid = b.uid
-> WHERE
-> a. NAME = ‘mike‘
-> GROUP BY
-> a.uid
-> HAVING
-> count(b.oid) < 2;
+-----+-------+
| uid | total |
+-----+-------+
| ccc | 1 |
| ddd | 0 |
+-----+-------+
rows in set (0.00 sec)mysql> SELECT
-> a.uid,
-> count(b.oid) AS total
-> FROM
-> table1 AS a
-> LEFT OUTER JOIN table2 AS b ON a.uid = b.uid
-> WHERE
-> a. NAME = ‘mike‘
-> GROUP BY
-> a.uid
-> HAVING
-> count(b.oid) < 2
-> ORDER BY
-> total DESC;
+-----+-------+
| uid | total |
+-----+-------+
| ccc | 1 |
| ddd | 0 |
+-----+-------+
rows in set (0.00 sec)mysql> SELECT
-> a.uid,
-> count(b.oid) AS total
-> FROM
-> table1 AS a
-> LEFT JOIN table2 AS b ON a.uid = b.uid
-> WHERE
-> a. NAME = ‘mike‘
-> GROUP BY
-> a.uid
-> HAVING
-> count(b.oid) < 2
-> ORDER BY
-> total DESC
-> LIMIT 1;
+-----+-------+
| uid | total |
+-----+-------+
| ccc | 1 |
+-----+-------+
row in set (0.00 sec)至此SQL的解析之旅就结束了,上图总结一下:
