LuoXinLoves 2019-12-24
函数如下:
create or replace FUNCTION fn_rme_split(p_str IN VARCHAR2,
p_delimiter IN VARCHAR2)
RETURN rme_split
PIPELINED IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2(4000);
BEGIN
len := LENGTH(p_str);
len1 := LENGTH(p_delimiter);
WHILE j < len LOOP
j := INSTR(p_str, p_delimiter, i);
IF j = 0 THEN
j := len;
str := SUBSTR(p_str, i);
PIPE ROW(str);
IF i >= len THEN
EXIT;
END IF;
ELSE
str := SUBSTR(p_str, i, j - i);
i := j + len1;
PIPE ROW(str);
END IF;
END LOOP;
RETURN;
END fn_rme_split;测试如下:
1 select temp.ass_code 2 from (SELECT COLUMN_VALUE AS ass_code 3 FROM TABLE(rme_delete.fn_rme_split(‘a,b,c,d,e,f ‘,‘,‘))) temp;执行结果如下:
