星愿 2019-12-27
1.语法文法G[E]如下所示:
–E→E+T | E-T | T
–T→T* F | T/F | F
–F→P^ F | P
–P→(E) | i
解:
E -> E+T { E.place := newtemp; emit( E.place , ‘ := ‘ , E.place , ‘ + ‘ , T.place )}
E -> E-T { E.place := newtemp; emit( E.place , ‘ := ‘ , E.place , ‘ - ‘ , T.place )}
E -> T { E.place := newtemp; emit( E.place , ‘ := ‘ , T.place )}
T -> T*F { T.place := newtemp; emit( T.place , ‘ := ‘ , T.place , ‘ * ‘ , F.place )}
T -> T/F { T.place := newtemp; emit( T.place , ‘ := ‘ , T.place , ‘ / ‘ , F.place )}
T -> F { T.place := newtemp; emit( T.place , ‘ := ‘ , F.place )}
F -> P^F { F.place := newtemp; emit( F.place , ‘ := ‘ , P.place , ‘ ^ ‘ , F.place )}
F -> P { P.place := newtemp; emit( F.place , ‘ := ‘ , P.place )}
P -> (E) { P.place := E.place;}
P -> i { if i <> nil then emit( P.place , ‘:=‘ , i.place ) else error}
2.(选做)实验三:语法制导的语义翻译程序
要求:
如
输入:a+b*c,则输出
(*,b,c,T1)
(+,a,T1,T2)
输入:b*(c+b)*d,则输出
(*,b,c,T1)
(*,b,d,T2)
(+,T1,T2,T3)