Python3调用微信企业号API发送文本消息代码示例

本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码，具体如下：

#!/usr/bin/env python
# -*- coding:utf-8 -*-
import urllib.request
import json
import sys
import logging
touser = '@all'
agentid = 0
corpid = 'wx5aef2da956514535'
corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0'
url = 'https://qyapi.weixin.qq.com'
subject = sys.argv[2]
message = sys.argv[3]
logging.basicConfig(level=logging.DEBUG, filename='E:\Python_project\Scripts\my.log',
          format='%(asctime)s - %(levelname)s: %(message)s')
class Weixin:
  def __init__(self, url, corpid, corpsecret):
    token_url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url, corpid, corpsecret)
    self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token']
  def send_message(self, url, data):
    send_url = '%s/cgi-bin/message/send?access_token=%s' % (url, self.token)
    self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url, data=data)).read()
    x = json.loads(self.respone.decode())['errcode']
    if x == 0:
      logging.debug('Successfully %s  %s' % (subject, message))
      return 'Succesfully'
    else:
      logging.debug('Failed %s  %s' % (subject, message))
      return 'Failed'
  def messages(self, subject, message):
    values = {
      "touser": touser,
      "msgtype": 'text',
      "agentid": agentid,
      "text": {'content': subject + message},
      "safe": 0
    }
    return self.send_message(url, bytes(json.dumps(values), 'utf-8'))
if __name__ == '__main__':
  obj = Weixin(url, corpid, corpsecret)
  ret = obj.messages(subject, message)

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