pythoning 2015-03-20
本文实例讲述了python使用三角迭代计算圆周率PI的方法。分享给大家供大家参考。具体如下:
方法1:
代码如下:
# Calculating PI using trigonometric iterations # FB36 - 20130825 import math x = 1.0 y = 1.0 z = 1.0 w = 1.0 v = 1.0 u = 1.0 for i in range(30): x = math.sin(x) + x y = math.cos(y) + y z = math.cos(z) + math.sin(z) + z w = math.cos(w) - math.sin(w) + w v = math.cos(v) * math.sin(v) + v u = math.cos(u) / math.sin(u) + u print i print x, y * 2.0, z * 4.0 / 3.0, w * 4.0, v * 2.0, u * 2.0 print
方法2:
代码如下:
# Calculating PI using trigonometric iterations # FB36 - 20130901 import math def sin2(x): return ((math.e ** complex(0.0, x) - math.e ** complex(0.0, -x)) / 2.0).imag def cos2(x): return ((math.e ** complex(0.0, x) + math.e ** complex(0.0, -x)) / 2.0).real x = 1.0 y = 1.0 x2 = 1.0 y2 = 1.0 for i in range(5): x = math.sin(x) + x y = math.cos(y) + y x2 = sin2(x2) + x2 y2 = cos2(y2) + y2 print i, x, x2, y * 2.0, y2 * 2.0
希望本文所述对大家的Python程序设计有所帮助。