AJAXBloger 2013-02-28
首先,我会想到以下两个问题:
1、Web端是如何通过Ajax发送异步请求的?又如何接收Server端响应的JSON数据?
2、Server端收到请求后,如何返回JSON数据?
一、使用Ajax发送异步请求,并接收Server端传回的响应数据:
先看JSP页面代码:
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%> <%@ taglib prefix="s" uri="/struts-tags" %> <html> <head> <title>Struts+Ajax+JSON</title> <script type="text/javascript" src="ajax.js"></script> </head> <body> <h3>Struts2 + Ajax + JSON 整合</h3> <form action="json" method="get"> username:<input type="text" id="username" name="user.username" /><br/> password:<input type="text" id="password" name="user.password" /><br/> <input type="button" onclick="getEmail()" value="查看Email"/><br /> </form> <p>您的Email地址为:<span id="email"></span></p> </body> </html>
前端实现Ajax的JS代码:
//创建XMLHttpRequest对象 function createXMLHttpRequest() { var xmlhttp; if(window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); } else { if(window.ActionXObject) { xmlhttp = new ActionXObject("Microsoft.XMLHTTP"); } else { xmlhttp = new ActionXObject("Msxml2.XMLHTTP"); } } return xmlhttp; } //发送GET请求 function sendGetRequest(url,callback){ var xmlhttp = createXMLHttpRequest(); xmlhttp.open("GET", url, true); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4) { if (xmlhttp.status == 200) { //获取服务器的响应数据 var data = xmlhttp.responseText; callback(data); } } }; xmlhttp.send(null); } //获取Email地址 function getEmail() { var username = document.getElementById("username").value; var password = document.getElementById("password").value; var url = "json?user.username=" + username + "&user.password=" + password; sendGetRequest(url, function(data){ var obj = eval("(" + data + ")"); document.getElementById("email").innerHTML = obj.user.email; }); }
二、使用Struts2处理异步请求并返回JSON数据:
Struts2中的Action代码:
package com.json.action; import java.io.IOException; import java.io.PrintWriter; import javax.servlet.http.HttpServletResponse; import net.sf.json.JSONObject; import org.apache.struts2.ServletActionContext; import com.json.dto.User; import com.opensymphony.xwork2.ActionSupport; public class UserAction extends ActionSupport { private User user; //此方法的返回类型为void public void execute() throws IOException { //打印请求中的user参数 System.out.println(user.getUsername() + ":" + user.getPassword()); //---发送JSON数据--- HttpServletResponse response = ServletActionContext.getResponse(); response.setContentType("text/html"); PrintWriter out = response.getWriter(); user.setEmail("[email protected]"); //创建JSON对象 JSONObject json = new JSONObject(); //把User对象放入Json对象中 json.accumulate("user", user); //把Json对象转成字符串并写入响应流 out.print(json.toString()); //可以打印JSON文本看一看 System.out.print(json.toString()); out.flush(); out.close(); } public User getUser() { return user; } public void setUser(User user) { this.user = user; } }
Action中的User类的代码:
package com.json.dto; public class User { private String username; private String password; private String email; public User() {} public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } }
struts.xml文件的配置:
<?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd"> <struts> <package name="user" extends="struts-default"> <action name="json" class="com.json.action.UserAction" method="execute"> </action> </package> </struts>
J2EE开发中使用JSON时需要导入以下5个jar包:
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commons-lang-2.4.jar
commons-logging-1.1.1.jar
json-lib-2.4-jdk15.jar
ezmorph-1.0.6.jar
commons-collections-3.2.1.jar
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已全部打包在附件内:
结束数据方法的参数,该如何定义?-- 集合为自定义实体类中的结合属性,有几个实体类,改变下标就行了。<input id="add" type="button" value="新增visitor&quo
本文实例讲述了php+ ajax 实现的写入数据库操作。分享给大家供大家参考,具体如下:。<input class="tel" type="text" placeholder="请输入您的手机号码&q