ajaxtony 2011-09-20
代码如下:
$.post('<%=this.AppPath %>DataService/InventoryUIService.svc/Rename', ///location.protocol + "//" + location.host + location.pathname + "/Rename", odata, function (result) { $dialogProcessing.dialog("close"); if (result.Success) { alert("Success"); } else { var msg = "Your submit fauiler, Detail message is:" + result.ErrorMessage; window.alert(msg); } }, "json"); $.ajax({ url: '<%=this.AppPath %>DataService/InventoryUIService.svc/Rename', type: 'POST', contentType: 'application/json', dataType: 'json', data: odata, success: function (result) { if (result.Success) { alert("Success"); } else { var msg = "Your submit fauiler, Detail message is:" + result.ErrorMessage; window.alert(msg); } }, error: function (jqXHR, textStatus, errorThrown) { var msg = "Your submit throw a error, \r\nError message is:" + $(jqXHR.responseText).text(); window.alert(msg); } });
$.post:
$.ajax:
感觉$.post是用来提交forms的,而要跟wcf ajax service访问,还必须得用$.ajax来指定Content-Type.
后来找到的资料: http://stackoverflow.com/questions/2845459/jquery-how-to-make-post-use-contenttype-application-json
结束数据方法的参数,该如何定义?-- 集合为自定义实体类中的结合属性,有几个实体类,改变下标就行了。<input id="add" type="button" value="新增visitor&quo
本文实例讲述了php+ ajax 实现的写入数据库操作。分享给大家供大家参考,具体如下:。<input class="tel" type="text" placeholder="请输入您的手机号码&q