ajaxtony 2011-09-20
代码如下:
$.post('<%=this.AppPath %>DataService/InventoryUIService.svc/Rename', ///location.protocol + "//" + location.host + location.pathname + "/Rename",
odata,
function (result) {
$dialogProcessing.dialog("close");
if (result.Success) {
alert("Success");
}
else {
var msg = "Your submit fauiler, Detail message is:" + result.ErrorMessage;
window.alert(msg);
}
},
"json");
$.ajax({
url: '<%=this.AppPath %>DataService/InventoryUIService.svc/Rename',
type: 'POST',
contentType: 'application/json',
dataType: 'json',
data: odata,
success: function (result) {
if (result.Success) {
alert("Success");
}
else {
var msg = "Your submit fauiler, Detail message is:" + result.ErrorMessage;
window.alert(msg);
}
},
error: function (jqXHR, textStatus, errorThrown) {
var msg = "Your submit throw a error, \r\nError message is:" + $(jqXHR.responseText).text();
window.alert(msg);
}
}); $.post:

$.ajax:

感觉$.post是用来提交forms的,而要跟wcf ajax service访问,还必须得用$.ajax来指定Content-Type.
后来找到的资料: http://stackoverflow.com/questions/2845459/jquery-how-to-make-post-use-contenttype-application-json
结束数据方法的参数,该如何定义?-- 集合为自定义实体类中的结合属性,有几个实体类,改变下标就行了。<input id="add" type="button" value="新增visitor&quo
本文实例讲述了php+ ajax 实现的写入数据库操作。分享给大家供大家参考,具体如下:。<input class="tel" type="text" placeholder="请输入您的手机号码&q